Review: Smullyan & Fitting, Set Theory and the Continuum Problem

The first sentence of Pollard’s review sums up my feelings perfectly: “This rewarding, exasperating book…” On balance, I found it more exasperating than rewarding. But it does have its charms.

I participated in a meetup group that went through the first two parts of S&F. My fellow participants possessed considerable mathematical knowledge and sophistication, but had only slight prior acquaintance with mathematical logic and none with axiomatic set theory. (The opinions here are strictly my own, but they reflect my experience in the meetup.) If I had just skimmed the book, glancing at familiar material, I would probably have a more positive impression.

I wrote an extensive set of notes for the meetup. This post is basically the last section of those notes.

I will begin with the book’s minuses, so as to end on a positive note.

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Stirling’s Formula: Ahlfors’ Derivation

If you’re reading this blog, you probably know Stirling’s formula:

n! \sim \sqrt{2\pi n}\left(\frac{n}{e}\right)^n

It’s not hard to estimate n! to within a factor of √2; I wrote up a note on this and even easier derivations. It’s quite a bit harder to show that the ratio of the two sides approaches a definite limit as n→∞ and that this limit is 1. You can find a variety of proofs in a number of places, one being Ahfors’ Complex Analysis.  I wrote up a note about this too, expanding on some of the details.

Incidentally, the two sides are asymptotic not just for positive integers n. Replace n! with Γ(z+1) on the left, and both n‘s with z‘s on the right. Allow z to go to infinity in the complex plane, while staying at least a fixed finite distance to the right of the imaginary axis. Then the two sides remain asymptotic. Ahfors proves this stronger result, and uses it to derive the integral form for the Γ function.

Note that if you replace the n‘s with z‘s, you have zz on the right. So you’ve got to worry about branches of the complex logarithm (since zz is defined as ez log z). The note deals with this (and other things).

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First-Order Categorical Logic 4

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MW: I made up a little chart to help me keep all these adjoints straight:

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First-Order Categorical Logic 3

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JB: Okay, let’s talk more about how to do first-order classical logic using some category theory. We’ve already got the scaffolding set up: we’re looking at functors

B \colon \textrm{FinSet} \to \textrm{BoolAlg}.

You can think of B(S) as a set of predicates whose free variables are chosen from the set S. The fact that B is a functor captures our ability to substitute variables, or in other words rename them.

But now we want to get existential and universal quantifiers into the game. And we do this using a great idea of Lawvere: quantifiers are adjoints to substitution.

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Non-standard Models of Arithmetic 11

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MW: Time to start on Enayat’s paper in earnest. First let’s review his notation. M is a model of T, a recursively axiomatizable extension of ZF. He writes \mathbb{N}^M for the ω of M equipped with addition and multiplication, defined in the usual way as operations on finite ordinals. So \mathbb{N}^M is what he calls a T-standard model of PA.

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Non-Standard Models of Arithmetic 10

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JB: So, last time you sketched the proof of the Paris–Harrington theorem. Your description is packed with interesting ideas, which will take me a long time to absorb. Someday I should ask some questions about them. But for now I’d like to revert to an earlier theme: how questions about the universe of sets cast their shadows down on the world of Peano arithmetic.

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First-Order Categorical Logic 2

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MW: So let’s see. Last time we talked about the functor B from the category FinSet to the category BoolAlg of boolean algebras. Liberal infusions of coffee convinced you that B is covariant; I accidentally suggested it was contravariant. I think I’ve come round to your position, but I still have a couple of things I want to say on the matter. If it won’t be too confusing for our readers.

JB: Okay.  If we’re planning to talk more about the variance, it’s probably good to start out by getting the reader a bit confused.  I used to always be confused about it myself.  Then I finally felt I had it all straightened out.  Then you shocked me by arguing that it worked the opposite way.  Your argument was very sneaky.

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